CGPA to Percentage Calculator

CBSE Class XI Admissions(SHARE)

OXFORD SCHOOLs By Oxfordschools

Re-Checking/Verification of Marks | Improvement Exam | Class XI Admissions

Subject Wise Percentage

Subject	Grade	Grade Point
English	? A1 A2 B1 B2 C1 C2 D E1 E2		=		%
Science	? A1 A2 B1 B2 C1 C2 D E1 E2		=		%
Mathematics	? A1 A2 B1 B2 C1 C2 D E1 E2		=		%
Social Science	? A1 A2 B1 B2 C1 C2 D E1 E2		=		%
Hindi	? A1 A2 B1 B2 C1 C2 D E1 E2		=		%
Sanskrit	? A1 A2 B1 B2 C1 C2 D E1 E2		=		%
Optional	? A1 A2 B1 B2 C1 C2 D E1 E2		=		%
Optional	? A1 A2 B1 B2 C1 C2 D E1 E2		=		%

By Oxfordschools

Overall Percentage

CGPA		Percentage
	=>	%

By Oxfordschools

Grading Pattern

Instructions

The CGPA is the average of Grade Points obtained in all the subjects excluding additional 6^th subject as per Scheme of Studies.
An indicative equivalence of Grade Point and Percentage of Marks can be assessed as follows:

• Subject wise indicative percentage of marks = 9.5 x GP of the Subject.
  
• Overall indicative percentage of marks = 9.5 x CGPA

The above formula given by CBSE to convert grades into marks and percentage is only an approximation and not exact.

.:: FAQS ::.

Full Form of CGPA ?

Cumulative Grade Point Average.

What is CGPA ?

It is an overall indicative percentage of marks.

How to calculate percentage from CGPA ?

Multiply the CGPA with 9.5 or use the above calculator to get the indicative percentage.

Why multiply with 9.5 only ?

The Board took the result of the last five years and calculated the average marks of all candidates who had scored between 91 and 100. That average turned out to be close to 95 marks. Since the equivalent Grade Point for the 91-100 band (A1 grade) of marks is 10, it then divided the average result of 95 by 10. The result is 9.5.

Download IIT JEE 2010 question paper, solution (Key), cutoff, rank calculator

Download here free IIT JEE 2010 question paper with solution, Rank calculator is also give to know your rank.

Download Question paper 1 with solution  of IIT JEE 2010 at THIS LINK

Download Question paper 2 with solution of IIT JEE 2010 at THIS LINK

(right click the link and save it the pdf file)

More than 4,00,000 candidates appeared in IIT JEE 2010 exam on 11th April 2010.

There was two paper of 3 hour each. Each paper consists of questions from Physics, Chemistry and maths.

Full marks of physics, chemistry and maths was 163 each.

Minimum cutoff marks for each subject is around 20 marks.

You can Check your rank at by submitting your marks. by Clicking on Star

Here is the Approximate marks Vs Rank Details

MARKS (out of 489) =  RANK

0-150  = more than 9000

150-180 =  6000- 8500

180-210 = 3000- 8000

210- 240= 500- 3000

240 and above = you are in top 500

Best of luck for your result.