Wings Of Knowledge....: May 2013

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Tuesday, May 28, 2013

Class Xth CBSE result announced...

CBSE Class Xth result announced on

CBSE - Class X Examination - Announced on 30^th May 2013

source:- Dainik Jagran

Monday, May 27, 2013

JEE (Main) 2013 - Frequently Asked Questions about Normalization

JEE (Main) 2013 - Frequently Asked Questions about Normalization

Q. What will be my normalized Board marks based on my Board and JEE (Main) Score?

A. Your normalized Board marks will be based on your position in the Board (i.e. your percentile score). The percentile score you get in your board will mainly contribute to your normalized marks. Please see example.

Q. I could not do well in JEE (Main) but have done very well in Board exam, will I qualify for appearing in JEE (Advanced) after getting weightage of normalized Board marks?

A. No, the normalized Board marks weightage is only for deciding ranking of JEE (Main) which will be used for admission to all Central Funded Technical Institutions (CFTIs)/ NITs/IIITs but excluding IITs).

Q. As written, the five subjects will be taken into account for calculation of percentile and normalization are 1-Language, 2-Physics, 3-Mathematics, 4-Chemitry (any one of Chemistry, Biology, Computer Science, Biotechnology), 5-Any Elective or Language. Can this 5^th subject be Computer Science as I have already taken Chemistry from PCM Science group?

A. Yes, the 5^th subject can also be any of the four subjects which are given at Sl No. 4 above. However no subject should be repeated.

Q. I have studied five subjects English, Physics, Chemistry, Mathematics and Computer Science. Since Computer Science falls under the same Science group, will it be considered as fifth subject?

A. Yes, Computer Science will be treated as fifth subject in this case.

Q.If I do well in additional sixth subject then will it be accounted for in place of subject Physics, Mathematics, at least One from Chemistry/Biology/Computer Science/Biotechnology?

A. No. The subjects required should meet eligibility criteria, i.e. one language, Physics, Mathematics, one from Chemistry/Biology/ Biotechnology/Computer Science and one any Elective or Language.

Q. I have only four subjects in my Board examination, whereas 5 subjects has been mentioned in the scheme of study for Science to be considered for admission to NITs, IIITs. Will I be considered?

A. For this year as an exception, the candidates with four subject will also be considered provided the subject combination satisfies the eligibility condition of JEE-Main.

Q. The variable/symbol B₀ is not used anywhere in the normalization formula given in the "Normalisation Procedure" document.

A. The B₀ is the marks obtained by the candidate in his/her Board, which is the basis for calculating percentile (P). Hence variable B₀ is only a base for calculating percentile (P), which is further used to get corresponding JEE (Main) marks.

Q. What will be the minimum marks that should be scored in class 12^th Board exam to be qualified for admission in IIT?

A. This is dealt by JEE (Advanced), please send your query to jeeadv@admin.iitd.ac.in

Q. Some Boards like CBSE give grades for few subjects such as Work Experience etc, will these grades be also considered for fifth subject while normalizing score?

A. Such subjects are not considered for the purpose of normalization.

Q.I have appeared in class 12^th Science stream examination with English Core, Physics, Chemistry, Mathematics and Computer Science. Is my subject combination is correct for JEE (Main)?

A.Yes.

Q. I have scored 423 out of 500 marks in my Board examination and was JEE (Main) Paper-1 score is 180. What will be my normalized marks for JEE (Main)?

A. Your normalized marks will be based on your percentile rank within your Board. The equivalent marks of JEE (Main) percentile (All India) and JEE (Main) percentile (of that Board) will be taken into consideration based on your board percentile score.

In order to calculate normalized board marks, one needs to know marks of all the students in that Board, marks of all the student of that Board in JEE (Main), as well as marks of all the students of all the Boards in JEE (Main). Please see example.

Calculate GATE percentile 2013

As everyone knows GATE scores are used for M.Tech (other master degrees in Engineering) and percentiles tells you where you stand. Please don’t confuse yourself with percentage.

Percentile is a relative term and tells where you stand in a set of people. For example, if you have 99.95 percentile in GATE means that your score or marks are above 99.95% student who took GATE exam.

Whereas, percent is a relative and measured on the scale of 100, it means that how many marks you got out of 100. This is not a measure of GATE performance. Therefore, don’t worry if someone says you that they go 99.9X score and think that it is beyond your capacity. To answer how to find GATE percentile please read the below formula and example carefully.

The GATE percentile is calculated as follows:

P = ( (N- your rank)/ N) x 100

Where P is percentile and N is total number of candidates appeared for exam.
(N- Your rank) indicates the number of candidates who have scored less marks than you.

For example, if total number of candidates are 100 and 90 of them have less marks than you P = (09/100)X100 = 0.9×100 = 90 percentile.

For another example: A guy form Mechanical Engineering have All India Rank (AIR) 99 and total number of student of students appeared for GATE in Mechanical Engineering are 59338 in 2010. Then his percentile would be calculated as

P = ((59338-99)/ 59338) X 100
= (59239/59338) X 100
= (0.9983) X 100
= 99.83
The candidate has 99.83 percentile.

As the competition grown too high, refer to GATE 2010 analysis, percentile not used for admissions anymore. As score is calculated on 1000 scale it gives a bit clear understanding and make admission process easy. Therefore Score is taken into consideration these days. Please refer to what is valid GATE Score to know more about GATE Scores. Do check for more information of GATE and M.Tech Admissions.

Source:- inspirenignite.com

JEE Advanced 2013 Percentile Calculation of CUTOFF Percentile -

CBSE has released FAQs about the normalization of Score in JEE Main 2013 which will help the candidates to have a better understanding of merit list preparation and score generation.

CLICK HERE to see the process of detailed calculation of Percentile Marks

The FAQs are as follows:

Q1. What will be the CBSE Normalization of Board Score based on JEE Main and Board Score?

Ans1. The normalized Board Score will be based on candidates’ position in Board i.e. the percentile score of a candidate. Candidates’ Board Percentile will mainly contribute to Normalized Score as per CBSE Normalization.

Q2. I wasn’t able to do well in JEE Main 2013 but my Board exams were good, would I be able to qualify for JEE Advanced 2013 after getting weightage of Normalized Board Marks?

Ans2. NO, the normalized Board marks will be ONLY for deciding JEE Main ranking. As per CBSE Normalization, this will be used for admission in all Central Funded Technical Institutions: CFTIs, NITs, IIITs excluding IITs.

Q3. As mentioned in the earlier notifications of CBSE Normalization, 5 subjects will be considered for percentile calculation and normalization which are: 1 – Language, 2 – Physics, 3 – Mathematics, 4 – Chemistry (any one of Biology, Chemistry, Biotechnology and Computer Science), 5 – Any Elective or Language. Can Computer Science this FIFTH subject as I have already taken the subject of Chemistry from the PCM Science group?

Ans3. YES. The 5^th Subject can also be any of the FOUR subjects which are given after S. No. 4 above. However, no subject can be REPEATED for CBSE Normalization.

Q4. I have taken 5 subjects of English, Physics, Chemistry, Mathematics and Computer Science. As Computer Science will fall under same Science Group, can it be considered as FIFTH Subject?

Ans4. YES. As per the norms of CBSE Normalization in this case, Computer Science will be treated as FIFTH Subject.

Q5. If I score well in Sixth Subject then can it be counted in place of the subjects of Mathematics, Physics, and at least ONE from Biology/Chemistry/Biotechnology/Computer Science?

Ans5. NO. The required subjects should meet the eligibility criteria, i.e. One language, Mathematics, Physics, One from Chemistry/Biotechnology/Biology/Computer Science and any one Language or Elective.

Q6. In my Board Exam, I have only 4 subjects, whereas CBSE Normalization has specified 5 subjects in the scheme of Science Study for admissions in NITs, IIITs. Will I be considered?

Ans6. It has been made an exception for this year only. Candidates with 4 subjects will ALSO be considered given that their subject combination satisfies JEE Main Eligibility.

Q7. In the CBSE Normalization procedure document released earlier by the Board the symbol B₀has not been used anywhere for Normalization.

Ans7. B₀refers to the marks obtained by candidates in their Board, and forms the basis for calculating percentile (P). Therefore, B₀is just a base value to calculate the percentile score which must be secured to get corresponding JEE Main 2013 marks.

Q8. In order to qualify for admission in IITs, what should be the minimum score in class XII as per CBSE Normalization?

Ans8. All the queries of such kind will be handled by JEE Advanced and should be sent to: jeeadv@admin.iitd.ac.in.

Q9. CBSE also has grading procedure for some subjects such as Work Experience etc, will these grades be considered for 5^th subject while CBSE Normalization of scores?

Ans9. NO. Such subjects will not be considered for normalization.

Q10. I have taken the Class XII exam with the subjects of Physics, Chemistry, English Core, Mathematics and Computer Science. Is this subject combination right for JEE Main 2013?

Ans10. Yes.

Q11. My Board’s Score is 423 out of 500 and my JEE Main score for Paper 1 is 180. What will be my normalized marks for JEE Main as per CBSE Normalization?

Ans11. The normalization will be based on candidates’ percentile rank within his/her Board. The equivalent percentile marks of JEE Main and JEE Main Percentile of that Board will be considered on the basis of Board Percentile Score. As per CBSE Normalization, every candidate has to know marks of all the students of that Board, marks of all students of same Board in JEE Main and marks of all the students of all the Boards in JEE Main exam.

Percentile Calculation:

JEE Main or Board percentile will reflect what percentage of candidates have secured below that candidate in THAT Board or JEE Main Exam. e.g. 20^th Percentile is value below which 20% of observations can be found.

The Percentile can be calculated as:
100 X (Number of candidates in the “Group” with aggregate marks less than candidate/ Total Number of candidates in the “group”).

Suppose there are 13711 candidates in a Board and a candidate who has scored 60% of Board Marks has 6865 below him/her. Then the percentile score will be calculated as:

Percentile score for 60% of Board Marks= (6865/13711) X 100

Percentile= 50.07

Information about Joint Entrance Examination (Main) – 2013

Joint Entrance Examination (Main) – 2013

JEE Main 2013 for Admission to Undergraduate Engineering Programs at NITs, IIITs, Other centrally funded Technical Institutions, Institutions funded by several participating State Governments, and several other Institutions shall include the performance in the class 12/other Qualifying Examination and in the Joint Entrance Examination, JEE (Main). The Paper-1 of JEE (Main) will also be an eligibility test for the JEE (Advanced), which the candidate has to take if he/she is aspiring for admission to the undergraduate programmes offered by the IITs.